Question

Design a differentiator circuit for a square wave signal with Vpp=10 and frequency 10KHz.​

Answer 1

Answer:

Step 1 :

Choose fa equal to the highest frequency of the input signal. In this case fa = 1KHz

fa=12πRFC1

Let C1 = 0.1μf

1KHz=12πRF×0.1µf

RF=1.59KΩ

Step 2 :

Choose fb = 10 fa

fb=10K=12πR1C1

10K=12πR1×0.1µf

R1=159.15Ω

Step 3 :

Calculate the values of CF, so that R1C1 = RFCF

159.15Ω×0.1µf=1.59KΩ×CF

CF=0.01µf

Explanation:

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Answer 2

Step 1 :

Choose fa equal to the highest frequency of the input signal. In this case $f_{a} =1kHz$

$f_{a} =12\pi RFC1$

Let $C_{1}=0.1$μ$f$

$1kHz=12\pi RF$×μ$f$

$RF=1.59k$Ω

Step 2 :

Choose $f_{b} =10f_{a}$

$f_{b} =10k$

$10k=12\pi R_{1}$×μ$f$

$R_{1} =159.15$Ω

Step 3 :

Calculate the values of $C_{F}$, so that R$R_{1} C_{1} =R_{F} C_{F}$

$159.15$Ω×0.1µf=1.59KΩ×$C_{F}$

$C_{F}$=0.01µf