Design a knuckle joint to transmit 150KN the design stresses may be taken us 75 Mpa in tension 60Mpa in shear and 150Mpa in compression
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Design of knuckle joint: Step 1) Diameter of Rod: d : =? Consider tensile failure of Rod 1. P =σt x A , 150 x 103 = 75 x π/4 xd2 , d = 50.4 mm 52 mm ( say)
Using Imperial relations Diameter of Knuckle pin Outside
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