Question

Design a problem, complete with a solution, to help other students better understand Kirchhoff’s Current Law. Design the problem by specifying values of ia, ib, and ic, shown in Figure, and asking them to solve for values of i1, i2, and i3. Be careful to specify realistic currents.​

Answer 1

Explanation:

KCL to obtain currents {i}_{1}, {i}_{2}i1,i2, and {i}_{3}i3 in the circuit shown in the Figure.

KCL to obtain currents {i}_{1}, {i}_{2}i1,i2, and {i}_{3}i3 in the circuit shown in the Figure.Solution

KCL to obtain currents {i}_{1}, {i}_{2}i1,i2, and {i}_{3}i3 in the circuit shown in the Figure.SolutionAt node a, 8 = 12 + {i}_{1} \rightarrow \underline{{i}_{1} = – 4A}8=12+i1→i1=–4A

KCL to obtain currents {i}_{1}, {i}_{2}i1,i2, and {i}_{3}i3 in the circuit shown in the Figure.SolutionAt node a, 8 = 12 + {i}_{1} \rightarrow \underline{{i}_{1} = – 4A}8=12+i1→i1=–4AAt node c, 9 = 8 + {i}_{2} \rightarrow \underline{{i}_{2} = 1A}9=8+i2→i2=1A

KCL to obtain currents {i}_{1}, {i}_{2}i1,i2, and {i}_{3}i3 in the circuit shown in the Figure.SolutionAt node a, 8 = 12 + {i}_{1} \rightarrow \underline{{i}_{1} = – 4A}8=12+i1→i1=–4AAt node c, 9 = 8 + {i}_{2} \rightarrow \underline{{i}_{2} = 1A}9=8+i2→i2=1AAt node d, 9 = 12 + {i}_{3} \rightarrow \underline{{i}_{3} = -3A}9=12+i3→i3=−3A