Design an experiment to carry out three reactions as below and test whether the product mixture is acidic, basic or neutral. How will you proceed to do that? a. 2HCl(aq) + Mg(s) → MgCl 2 (aq) + H 2 (g) b. 2HCl(aq) + CuCO 3 (s) → CuCl 2 (aq) + H 2 O(l) + CO 2 (g) c. KOH(aq) + HCl(aq) → KCl(aq) + H 2 O(l)
Answers
Answer:
Explanation:
(A) 2HCl(aq) + Mg(s) → MgCl 2 (aq) + H 2 (g)
In the given equation,
we know that hydrogen chloride in its aqueous form is acidic
because only acids react with metal to give salt and hydrogen.
In this case,
Mg is a metal and salt is MgCl2.
ACID + METAL = SALT + HYDROGEN
The product that is MgCl2 in aqueous form is neutral because
HCl is strong acid and when it reacts with Mg which is neutral gives neutral mixture.
*anhydrous(dry) MgCl2 is lewis acid which means a weak one as it is formed from a weak base and strong acid.
(B) 2HCl(aq) + CuCO 3 (s) → CuCl 2 (aq) + H 2 O(l) + CO 2 (g)
In the given equation,
HCl is a strong acid .
When it reacts with bases,it gives salt and water.
ACID + BASE = SALT + WATER
CuCl2 is a product obtained after the reaction between a strong acid and a weak base.
Thus,CuCl2 in it’s aqueous form is slightly acidic.
(C) KOH(aq) + HCl(aq) → KCl(aq) + H 2 O(l)
KOH is a strong base and similarly KCl is a also a strong acid.
Thus,
the product obtained will be neutral because neither ions can affect the acidity of a solution and the salt obtained will be neutral.