________designates the assumed value for the field. If it is not provided by the user input.
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Explanation:
EXAMPLE 1. CALCULATING THE ELECTRIC FIELD OF A POINT CHARGE
Calculate the strength and direction of the electric field E due to a point charge of 2.00 nC (nano-Coulombs) at a distance of 5.00 mm from the charge.
Strategy
We can find the electric field created by a point charge by using the equation
E
=
k
Q
r
2
.
Solution
Here Q = 2.00 × 10−9 C and r = 5.00 × 10−3 m. Entering those values into the above equation gives
E
=
k
Q
r
2
=
(
8.99
×
10
9
N
⋅
m
2
C
2
)
×
(
2.00
×
10
−
9
C
)
(
5.00
×
10
−
3
m
)
2
=
7.19
×
10
5
N/C
Discussion
This electric field strength is the same at any point 5.00 mm away from the charge Q that creates the field. It is positive, meaning that it has a direction pointing away from the charge Q.
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