Question

________designates the assumed value for the field. If it is not provided by the user input. ​

Answer 1

Explanation:

EXAMPLE 1. CALCULATING THE ELECTRIC FIELD OF A POINT CHARGE

Calculate the strength and direction of the electric field E due to a point charge of 2.00 nC (nano-Coulombs) at a distance of 5.00 mm from the charge.

Strategy

We can find the electric field created by a point charge by using the equation

E

=

k

Q

r

2

.

Solution

Here Q = 2.00 × 10−9 C and r = 5.00 × 10−3 m. Entering those values into the above equation gives

E

=

k

Q

r

2

=

(

8.99

×

10

9

N

⋅

m

2

C

2

)

×

(

2.00

×

10

−

9

C

)

(

5.00

×

10

−

3

m

)

2

=

7.19

×

10

5

N/C

Discussion

This electric field strength is the same at any point 5.00 mm away from the charge Q that creates the field. It is positive, meaning that it has a direction pointing away from the charge Q.