Math, asked by ramanahasi, 10 months ago

det of [ 2 45 55
1 29 32
3 68 87]​

Answers

Answered by shailajaakula86
12

Answer:

54

Step-by-step explanation:

2[29(87)-32(68)]-45[1(87)-3(32)]+55[1(68)-3(29]

54

Answered by SaurabhJacob
4

The determinant of the given matrix is 54.

Given,

\left[\begin{array}{ccc}2&45&55\\1&29&32\\3&68&87\end{array}\right]

To Find,

The determinant of the given matrix.

Solution,

For determinant, expanding matrix from column C1.

\left[\begin{array}{ccc}2&45&55\\1&29&32\\3&68&87\end{array}\right] = 2(29x87 - 68x32) - 1(45x87 - 68x55) + 3(45x32 - 29x55)

                      = 2(2523 - 2176) - 1(3915 - 3740) + 3(1440 - 1595)

                      = 2(347) - 1(175) + 3(-155)

                      = 694 - 175 - 465

                      = 54

Hence, the determinant of the given matrix is 54.

#SPJ3

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