Question

detailed solution find the answer

Answer 1

$x + \frac{1}{x} = 2 \cos( \alpha ) \\ ( {x + \frac{1}{x} )}^{2} = {(2 \cos\alpha })^{2} \\ {x}^{2} + { \frac{1}{ {x}^{2} } }^{2} + 2 = 4 \cos( \alpha ) \\ {x}^{2} + \frac{1}{ {x}^{2} } = 4 \cos( \alpha ) - 2$
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