Question

Detailly explain about (Frundlich adsorption isotherm .

$in \: matematical \: process \: explain \: it.$
Hoping great answers .

Please answer as soon as possible. ​

Answer 1

$\large \dag$ Question :-

Explain Freundlich adsorption isotherm briefly with mathematical calculations.

$\large \dag$ Answer :-

$\rm \purple \maltese \: \: \: \red{ \underline{ \underline{Freundlich \: Adsorption \: Isotherm }}}$

According to Freundlich adsorption isotherm the extent of adsorption is directly proportional to fractional power of pressure.

In mathematical form :-

$\bf \red\bigstar \: \: \orange{ \pmb{ \underbrace{ \underline{   \blue{  \frac{x}{m} \propto p {}^{ \ 1/n} \: \: \: }}}}}$

$:\longmapsto \rm \frac{ x }{m} = kp {}^{1/n} \: ; \small0 < n < 1\: \: - - - (1)$

❒ Taking log on both sides of (1) :

$:\longmapsto \rm log \frac{x}{m} = log( kp {}^{1/n} )$

$:\longmapsto \rm log \frac{x}{m} = log(k) + log( p {}^{1/n} )$

$:\longmapsto \rm log \frac{x}{m} = log(k) + \frac{1}{n} log( p ) - - - (2)$

Also graph of both equations are given in attachment.

Answer 2

Answer:

The variation in the amount of gas adsorbed per unit mass by the adsorbent with pressure at constant temperature is given by freundlich adsorption isotherm , the amount of gas adsorbed by it at a pressure decreases with an increase in temperature as confirmed by plots of these isotherms at different temperatures , now its validity can be proved by plotting log of gas adsorbed per unit mass of adsorbent at a temperature against log of pressure , if it comes out to be a straight line then the isotherm is true as log of any exponential function against the log of its variable is a straight line