Detect the presence of nitrogen atom in a given organic compound O
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The question asks detection of the presence of Nitrogen atom in an organic compound 'O'. But the exact organic compound has not been given. So, I am giving a general method for detecting the presence of Nitrogen atom in an organic compound.
Nitrogen atoms are covalently bonded to the organic compounds. So, to detect it, it has to be converted into its ionic form. This conversion is done by using sodium metal. This method is called as sodium fusion extract method or as Lassaigne's extract method.
The nitrogen and carbon that are present in the organic compound fuse with sodium metal to form sodium cyanide (NaCN), which is soluble in water.
Na + C + N → NaCN
Enough amount of ferrous sulphate is added, which results in the formation of sodium ferrocyanide.
6NaCN + FeSO₄ → Na₄[Fe(CN)₆] + Na₂SO₄
A Prussian blue precipitate indicating the presence of ferric ferrocyanide is formed due to the reaction of the generated ferric ions and ferrocyanide. This also indicates the presence of the Nitrogen atom.
Nitrogen atoms are covalently bonded to the organic compounds. So, to detect it, it has to be converted into its ionic form. This conversion is done by using sodium metal. This method is called as sodium fusion extract method or as Lassaigne's extract method.
The nitrogen and carbon that are present in the organic compound fuse with sodium metal to form sodium cyanide (NaCN), which is soluble in water.
Na + C + N → NaCN
Enough amount of ferrous sulphate is added, which results in the formation of sodium ferrocyanide.
6NaCN + FeSO₄ → Na₄[Fe(CN)₆] + Na₂SO₄
A Prussian blue precipitate indicating the presence of ferric ferrocyanide is formed due to the reaction of the generated ferric ions and ferrocyanide. This also indicates the presence of the Nitrogen atom.
Na₄[Fe(CN)₆] + Fe³⁺ → Fe₄[Fe(CN)₆]₃
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