Math, asked by rabiaboulhousn, 11 months ago

determime the numbers a,b,c such that a,b,c are three consecutive terms of a geometricsequence and an arithmetic sequence and abc=27

Answers

Answered by jessica99
0

X*2x*3x=27

6x

 {6} {x}^{3}   = 27


rabiaboulhousn: I guess It is wrong
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