Determinant of 3 x 3 matrix having first row [ 1 2 5], second row [ 3 5 7] and third row [ 4 5 0] will be ________.
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Answered by
5
Answer:
-14
i have found this determinant by considering 1st element of 1st row and 1st column then hide 1st column and 1 st row and multiply by 1st entry of 1 st column and 1 st row u will get 1(5×0- 7×5) similarly u can proceed further
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Answered by
4
Answer:
I think answer should be -4
Explanation:
|A| = 1(0-35) - 2 (0-28) + 5 (15-20)
|A| = -35 + 56 - 25
|A| = -60 + 56
|A| = -4
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