Determination of molecular formula of hydrocarbons using combustion data
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Example:
10cm3 of a gaseous hydrocarbon required 20 cm3 of oxygen for complete combustion. 10 cm3 of carbon dioxide was produced. Calculate the molecular formula of the hydrocarbon.
and
Suggested Solution:
Using the general equation and applying volume ratio, we have
CxHy (g) + (x + y/4) O2 (g) –> xCO2 (g) + y/2 H2O (l)
10cm3…… 20cm3 ……………….10cm3
1mol 2 mol 1 mol
Based on the above comparision, we have
x = 1 and (x + y/4) = 2
Solving it gives y = 4
Hence, the molecular formula of the hydrocarbon is CH4.
10cm3 of a gaseous hydrocarbon required 20 cm3 of oxygen for complete combustion. 10 cm3 of carbon dioxide was produced. Calculate the molecular formula of the hydrocarbon.
and
Suggested Solution:
Using the general equation and applying volume ratio, we have
CxHy (g) + (x + y/4) O2 (g) –> xCO2 (g) + y/2 H2O (l)
10cm3…… 20cm3 ……………….10cm3
1mol 2 mol 1 mol
Based on the above comparision, we have
x = 1 and (x + y/4) = 2
Solving it gives y = 4
Hence, the molecular formula of the hydrocarbon is CH4.
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