determination of molecular formulae:-
Answers
Answer:
here are some coding
Explanation:
doremon code
[tx]
<!DOCTYPE html>
<html lang="en">
<head>
<title>Doraemon</title>
</head>
<body>
<div class="head">
<div class="eye_white">
<ul>
<li><div class="eye_black"></div></li>
<li><div class="eye_black"></div></li>
</ul>
</div>
<div class="white">
<div class="line_left">
</div>
<div class="line_right">
</div>
<div class="nose"></div>
<div class="line_vertical"></div>
<div class="mouth"></div>
</div>
</div>
<style>
.head{
width:600px;
height:600px;
border-radius:100%;
background:#3c9dca;
border: black solid thick;
}
.white{
width: 524px;
height: 462px;
border-radius: 100%;
position: relative;
top: 120px;
left: 38px;
background: #FFF;
border: black solid thin;
z-index: 0;
}
.eye_white {
position: relative;
top: 60px;
left: 130px;
z-index: 1;
}
.eye_white li{
width: 125px;
height: 152px;
border-radius: 100%;
background: #FFF;
list-style:none;
border: black solid thin;
display:block;
float:left;
}
.eye_black{
width: 25px;
height: 45px;
border-radius: 100%;
background: #000;
list-style:none;
top: 80px;
position:relative;
border: black solid thin;
display:block;
left: 10px;
-webkit-animation:move 6s ease infinite;
animation:move 6s ease infinite;
}
@-webkit-keyframes move {
16%{top:95px;left:30px;}
32%{top:100px;left:60px;}
48%{top:80px;left:90px}
64%{top:100px;left:60px}
80%{top:95px;left:30px}
}
@keyframes move {
16%{top:95px;left:30px;}
32%{top:100px;left:60px;}
48%{top:80px;left:90px}
64%{top:100px;left:60px}
80%{top:95px;left:30px}
}
.eye_black::before{
content:'';
width: 10px;
height: 15px;
border-radius: 100%;
background: #fff;
list-style: none;
top: 16px;
position: relative;
display: block;
left: 7px;
}
.line_left{
width: 150px;
height:2px;
transform:rotate(20deg);
top: 90px;
left: 14px;
position:relative;
border-radius: 10%;
background: #000;
list-style: none;
display: block;
}
.line_left::before{
content:'';
width: 150px;
height:2px;
top: 70px;
transform:rotate(-20deg);
position:relative;
border-radius: 10%;
background: #000;
list-style: none;
display: block;
}
.line_left::after{
content:'';
transform:rotate(-40deg);
width: 150px;
height:2px;
top: 120px;
left: 30px;
position:relative;
border-radius: 10%;
background: #000;
list-style: none;
display: block;
}
.line_right{
width: 150px;
height:2px;
transform:rotate(160deg);
top: 90px;
left: 370px;
position:relative;
border-radius: 10%;
background: #000;
list-style: none;
display: block;
}
.line_right::before{
content:'';
width: 150px;
height:2px;
bottom: 100px;
position:relative;
transform:rotate(30deg);
border-radius: 10%;
background: #000;
list-style: none;
display: block;
left:20px;
}
.line_right::after{
content:'';
width: 150px;
height:2px;
bottom: 50px;
transform:rotate(10deg);
left: 0px;
position:relative;
border-radius: 10%;
background: #000;
list-style: none;
display: block;
}
.nose{
width: 45px;
height: 45px;
border-radius: 100%;
background: #b90319;
list-style: none;
top: 60px;
position: relative;
border: black solid thin;
display: block;
left: 236px;
z-index:2;
}
.nose::after{
content: '';
width: 15px;
height: 15px;
border-radius: 100%;
background: #FFF;
list-style: none;
top: 19px;
position: relative;
border: black solid thin;
display: block;
left: 9px;
}
.line_vertical{
width: 2px;
height: 310px;
top: 40px;
left: 258px;
position: relative;
border-radius: 10%;
background: #000;
z-index: 1;
}
.mouth{
width: 400px;
height: 400px;
border-radius: 100%;
top: -358px;
left: 62px;
position: relative;
background: #000;
z-index: -1;
}
.mouth::after{
content: '';
width: 402px;
height: 401px;
top: -4px;
left: -1px;
border-radius: 100%;
position: relative;
display: block;
background: #FFF;
}
</style>
</body>
</html>[/tex]
Answer:
Divide the molar mass of the compound by the empirical formula mass. The result should be a whole number or very close to a whole number. Multiply all the subscripts in the empirical formula by the whole number found in step 2. The result is the molecular formula.