Question

Determination of strength of kmno4 solutions by titrasion against standard M/10 mohr salt solution

Answer 1

M/10 Mohr’s salt is 4.9 Grams  of Mohr’s salt as-

0.1=x/392*4

Here, x = weight of Mohd salt = 4.9 grams

This, 4.9 g weight is added to 250 ml water to have M/10 Solution.

Now, the solution is kept under the buerette and KMno4 ( dark Pink) is added to solution, Hence titration occurs.

On experimental behalf’s around 11 ml or little bit up n down is the amount of KMno4 poured to Mohan salt solution .

It is observed when some of the HCL is added to it prior to titration chemical exploration tech.

Here , Once the Mohegan salt solution and KMno4 formed solution is neutralised POTASSIUM PERMANGANATE ACT AS A SELF INDICATOR ONLY AND SINCE SOLUTION FORMED AFTER TITRATION IS ACIDIC DUE TO PRIOR ADDED HCL , IT GIVES PINK COLOUR.

Now, going with the mathematical part of solution,

We know in Redox Rnx.(titration is redox rnx.)