Question

Determind the molecular formula oxide of iron which contain 69.9% and 30.1% by mass of oxide of iron in 159.89 gm/mol

Answer 1

fe2O4 as on after finding the emperical formula we will get FeO2 then on dividing molecular weight by emperical weight we will get approx 2 then we will multiply 2 in the whole eq. so we will get Fe2O4