Question

Determine a and b so that the curve y= ax³ + 3bx² has a point of inflection at ( -1, 2)

Answer 1

Answer:

y=ax  

3

+bx  

2

+cx+d

⇒y  

′

=3ax  

2

+2bx+c, differentiate given curve

⇒y  

′′

=6ax+2b

So for x=1 to be inflection point

y  

′′

∣  

x=1

​

=0

⇒6a(1)+2b=0⇒3a+b=0

Step-by-step explanation: