determine A.P whose 4th and 9th terms are 13 and 33
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4th term, 10th term are 13 and 25a+3d=13
a+9d=25
(a+9d)−(a+3d)=25−13
6d=12
d=2
a=7
First term =7, common difference =2
17th term=a+16d=39
Explanation:
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