Question

Determine a point charge that can given an electric field of magnitudes 100Nc-1 at a point 50cm away in free space.


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Answer 1

Given :-

point = 50 cm

Solution :-

E = k q/r²

$\sf \implies 100 = \dfrac{9 \times 10^{9}q }{0.5^{2} }$

$\sf \implies q = \dfrac{100 \times 0.5}{9 \times 10^{9} }$

q = 50/10⁻⁹

q = 2.78 x 10⁻⁹