Math, asked by pahingisagot00, 5 months ago

Determine a quadratic equation with the given roots
1. 2 and -1
2. -2 and -6
3. 3 and 4

Answers

Answered by rajeevr06
27

Answer:

if \:  \alpha  \: and \:  \beta  \: are \: roots \: of \: quadatic \: eq. \: then \:  \\ eq. \: is \:  \\  {x}^{2}  - ( \alpha  +  \beta )x +  \alpha  \beta  = 0

1. \:  \alpha  +  \beta  = 2 - 1 = 1 \:  \: and \:  \:  \alpha  \beta  =  - 1 \times 2 =  - 2 \\ so \: eq \: is \\  {x}^{2}  - x - 2 = 0

solve other same as above.

❤Thanks

Answered by Anonymous
59

Answer :

  • The quadratic equation formed by the roots 2 and (-1) is x² - x - 2 = 0

  • The quadratic equation formed by the roots (-2) and (-6) is x² + 8x + 12 = 0

  • The quadratic equation formed by the roots 3 and 4 is x² - 7x + 12 = 0

Explanation :

Given :

  • Roots of the first quadratic equation = 2 and (-1).

  • Roots of the second quadratic equation = (-2) and (-6)

  • Roots of the second quadratic equation formed = 3 and 4

To find :

  • Quadratic equations whose roots are given.

Knowledge required :

Formula for forming a quadratic equation :

⠀⠀⠀⠀⠀⠀⠀⠀⠀x² - (α + β)x + αβ = 0

Where :

  • α and β are the two roots of the equation

Solution :

Quadratic equation with roots of 2 and (-1) :

By using the formula for forming a quadratic equation and substituting the values in it, we get :

==> x² - (α + β)x + αβ = 0

==> x² - (2 + (-1))x + 2 × (-1) = 0

==> x² -(2 - 1)x + (-2) = 0

==> x² - x - 2 = 0

Quadratic Equation = - x - 2 = 0

Quadratic equation with roots of (-2) and (-6) :

By using the formula for forming a quadratic equation and substituting the values in it, we get :

==> x² - (α + β)x + αβ = 0

==> x² - [(-2) + (-6)]x + (-2) × (-6) = 0

==> x² - (-2 - 6)x + 12 = 0

==> x² - (-8)x + 12 = 0

==> x² + 8x + 12 = 0

Quadratic Equation = + 8x + 12 = 0

Quadratic equation with roots of 3 and 4 :

By using the formula for forming a quadratic equation and substituting the values in it, we get :

==> x² - (α + β)x + αβ = 0

==> x² - (3 + 4)x + 3 × 4 = 0

==> x² - 7x + 12 = 0

Quadratic Equation = - 7x + 12 = 0

Therefore,

  • The quadratic equation formed by the roots 2 and (-1) is x² - x - 2 = 0

  • The quadratic equation formed by the roots (-2) and (-6) is x² + 8x + 12 = 0

  • The quadratic equation formed by the roots 3 and 4 is x² - 7x + 12 = 0

amitkumar44481: Perfect :-)
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