determine (a) the acceleration and (b) the distance travelled in 6sec when a 7500N net force accelerates a 1500kg car uniformly from rest?
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Answered by
14
acceleration 5
distance 90
a=f/m
d= but+ 1/2atsquare
distance 90
a=f/m
d= but+ 1/2atsquare
Vikramkumat:
hope it will help u dear brother
yes, it did. thank you so much!
in which class u are brother
are you Korean
u are from Korea
Answered by
8
See my friend, As you have known that F=ma now by substituting values we get a (acceleration) as 5 m/s² Now, by second equation of motion we get S= 1/2(a)t² [as u is zero in this case] Now we get 90m as displacement.........
acc will be 5m/s2 and distance will be 90m
wrong answer dear
ooh sorry i think Tim is 5 but it is 6 sorry
iam really sorry dear
Yes displacement is 90m
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