Science, asked by rpavanece1904g8, 7 months ago

Determine Ac resistance of a p-n
junction diode having a forward biased.
voltage of 200mv & reverse saturation
current of I micro Ampere

Answers

Answered by Anonymous
13

Answer:

Answer:the ac resistance of semiconductor diode having a forward bias of 200 mv and reverse saturation current of 1 microampere at room temperature is 91.32 ohms.

Explanation: We know that Diode current is given by Shockley's equation,

Id=Is[e^(\frac{Vd}{n*Vt})-1] ...

Hence the AC resistance is= 200/2.19=91.32 ohms.

Explanation:

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