Determine all integer n such that n^4-n^2+64 is the square of an integer
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this question is like Pythagoras theorem
H²= P²⁺B²
P = √[n^4 - n^2]
= n√[n^2 - 1]
for n⁴⁻n²⁺64 to be sq of an integer
n = 0, ±1,
H²= P²⁺B²
P = √[n^4 - n^2]
= n√[n^2 - 1]
for n⁴⁻n²⁺64 to be sq of an integer
n = 0, ±1,
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