determine all natural numbers divisible by 8 whose sum of digits is less than 10 and the product of digits is equal yo 12
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am assuming that the digits are getting added repeatedly to finally arrive at a single digit and that digit should be 7. In other words, if the numbers are 196 or 259 or 34567 (for that matter), these all are candidate numbers because, for:
196: 1 + 9 + 6 = 16 = 1 + 6 = 7
259: 2 + 5 + 9 = 16 = 1 + 6 = 7
34567: 3 + 4 + 5 + 6 + 7 = 25 = 2 + 5 = 7
With this, we can very easily find the total Number of Numbers.
The answer is ( (10^8 – 7) / 9 ) + 1, which is nothing but
11111110 + 1, which is 11111111.
Thus the required answer is: 11,111,111.
Step-by-step explanation:
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