Determine all prime numbers a,b and c for which the expression x^2+b^2+c^2-1
is a perfect square
Answers
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Given:
Given expression is a² + b² + c² -1 is a perfect square.
To find:
Prime number a, b and c
Solution:
To find the integer solution we have ,
p₁² + p₂² + p₃² -1 = k²
here p = primes
We have to consider the equation modulo 8 to calculate this as the square modulo 8 are restricted to 0, 1, 4.
according to modulo 8, all odd primes square to 1 and 2² = 4.
now, going through all the possibilities we have valid possibility which are-
4 + 4 + 1 -1 =0 (mod 8 )
which means p₁ = p₂ = 2 and p₃ = odd
so, now original expression can be written as
2² + 2² + p₃² -1 = k²
k² - p₃² = 7
(k + p₃) (k - p₃) = 7
therefore,
k-p₃ = 1
k + p₃ = 7
values of k and p₃ are
k = 4 and p₃ = 3
Thus the only solution is
(p₁,p₂,p₃) = (2,2,3)
so, a, b and c are 2, 2, 3 respectively.