Question

determine all tye zeroes of a polynomial x⁴-x³+8x²+2x+12 if two zeroes are √2 and -√2​

Answer 1

Answer:

question is wrong there should be 20 in place of 12

Answer 2

p (x) = x⁴-x³+8x²+2x+12

two of its zeros are √2 and -√2

then (x+√2) and (x-√2) are the factors of p(x)

(x+√2) x (x-√2)

x²-2

or

x²+0x-2 [g(x)]

on dividing p(x) by g(x)

we will obtain q(x)

on further factorizing of q(x) we will obtain rest of the 2 zeros