Physics, asked by mandalsibu484, 9 months ago

Determine
ameter
comment drawn
drawn by the
shown in fig

Attachments:

Answers

Answered by kaushik05
14

First we have to find the equivalent resistance of the given circuit .

In the given circuit , 30 Ω and 5 Ω are in parallel combination :

As we know that , In parallel we use :

 \boxed{ \frac{1}{r}  =  \frac{1}{r_1}  +  \frac{1}{r_2}  + ....}

=> 1/R = 1/30 + 1/5 = (1+6)/30

=> 1/R = 7/30

=> R = 30/7 Ω

Now , All are in series combination :

As we know , in series we use ,

 \boxed{ \: r = r_1 + r_2 + ...}</p><p></p><p>

=> R = 30/7 + 10+5

=> R = (30+70+35)/7

=> R = 135/7 Ω

Given :

V = 9 v

R = 135/7 Ω

• Current = V/R

Current = 9×7 /135 = 63/135 = 0.466 Ampere

Hence, The value of current drawn by the ammeter is 0.466 A

Answered by parry8016
1

Explanation:

HERE IS U R ANSWER DEAR PLZ FOLLW ME

Attachments:
Similar questions