determine an A.p whose 3rd term is 16 and difference of 7th term and 5th term is 12
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A3=16,a7-a5=12
2d=12
D=6
A1=a3- 2d
=16-2×6=4
A5=A3+2d=16+12=28
A7=12+A5=12+28=40
2d=12
D=6
A1=a3- 2d
=16-2×6=4
A5=A3+2d=16+12=28
A7=12+A5=12+28=40
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