Determine an AP whose third is 16 and seventh term exceeds the fifth term by 12
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Answer: Given that the equations are,
a+2d=16
And , a+6d+12=a+4d
2d=-12
d=-6
And substitute d value in equation 1
a-12=16
a=28
Now, a=28, d=-6
The sequence is as : 28,22,16........
Step-by-step explanation:
Hope it helps you frnd.......
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