determine AP along 3rd term is 5 & 7th term is 9
Answers
Answer:
3,4,5...
Step-by-step explanation:
Let the first term be 'a' and common difference be 'd'.
3rd term = 5 → a + 2d = 5
=> a = 5 - 2d ... (1)
7th term = 9 → a + 6d = 9
=> a = 9 - 6d ... (2)
Compare (1) and (2):
=> 5 - 2d = 9 - 6d
=> d = 4/4 = 1
Further solve for a. On solving, a = 3.
Hence, the required AP is:
a, a + d, a + 2d,...
3, 3 + 1, a + 2(1)...
3, 4, 5...
Answer:
hope it help.....
Step-by-step explanation:
Let a and d be the first term and common difference of an AP
It is given that, third term a3 = 5 and seventh term a7 = 9.
Therefore,
a + 2d = 5 ... (i)
a + 6d = 9 ... (ii)
Subtracting (i) from (ii), we have
4d = 4
d = 1
Substituting in (i), we have
a + 2(1) = 5
a = 3
The AP will be a, a+d, a+2d, a+3d, ...
Hence, the required AP is 3, 4, 5, 6, 7,..........