Question

determine Ap where 3rd term is 5th and 7th term is9?????​

Answer 1

a+2d=5

a+6d=9

d=1

so a becomes...

a+6(1)=9

a=3

So AP is 3,4,5....

HOPE this helps u....

Answer 2

ARITHMETIC PROGRESSION :-

It is a list of numbers in which each term is obtained by adding a fixed number to the preceding term except the first term .

Some Important formulas of AP are ....

☆ an ( l ) = a + ( n - 1 ) d
☆ Sn = n / 2 ( 2a + ( n - 1 ) d ))
☆ an = Sn - S(n-1)

● Now here is the solution of your question ...

a3 = 5

a7 = 9

=> a + 2d = 5 _____(i)

and a + 6d = 9 ______(ii)

Now , subtracting eq (i) from eq (ii)

a + 6d = 9

- a + 2d = 5

_________

4d = 4

d = 1

Putting the value of d in eq (i) , we get ,

a + 2d = 5

a = 5 -2

a = 3

a2 = 3 +1

a2 = 4


Therefore the required AP is ......

AP = 3 , 4 , 5 , ....