Determine AP whose 3 term is subtracted from 7 term .we get 12
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Let 1st term of the ap=a
And common difference =d
Thus,
3rd term =a+2d
7th term =a+6d
ATQ
a+6d-(a+2d)=12
a+6d-a-2d=12
4d=12
d=3
a=any positive integer
And common difference =d
Thus,
3rd term =a+2d
7th term =a+6d
ATQ
a+6d-(a+2d)=12
a+6d-a-2d=12
4d=12
d=3
a=any positive integer
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