Determine AP Whose 3rd Term Is 11 And The 7th Term Is 29.
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Step-by-step explanation:
Solution :-
Let a be the 1st term and d be the common difference of the AP.
We have,
a₃ = 16
a + 2d = 16 ..... (i)
a₇ = a + 6d and a₅ = a + 4d
According to the questions,
⇒ a₇ - a₅ = 12
⇒ a + 6d - (a + 4d) = 12
⇒ a + 6d - a - 4d = 12
⇒ 2d = 12
⇒ d = 12/2
⇒ d = 6
Putting the value of d in equation (i), we get
a + 2 × 6 = 16
a + 12 = 16
a = 16 - 12 = 4
Here, a = 4, d = 6
Hence, AP is a, a + d, a + 2d, a + 3d +..
4, 4 + 6, 4 + 12, 4 + 18, ...
4, 10, 16, 22..
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