Determine AP ,whose 4th term is 18 and the difference of the 9th term from 5th term is 30
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It is given that 4th term is 18.
a4= 18
a + 3d = 18
a = 18 - 3d ... (1)
Also, a15- a9= a+14d - 1 - 8d = 30
6d = 30
d = 5
Thus, from (1), we get,
a = 18 - 15 = 3
Therefore, the AP is:
3,8,13,18,23 ......
Step-by-step explanation:
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