Question

Determine apparent depth of pool as observed by observer who is not looking at the base along the normal line, but rather looking at it as show​

Answer 1

Given:

Refractive index of water = $\sqrt{2}$

Refractive index of air = 1

Actual depth of the pool = 30 cm

To find:

Apparent depth of the pool.

Solution:

Since, the given phenomenon is due to refraction of the light.

Formula to get the apparent depth of the object,

$\frac{\text{Apparent depth of the object}}{\text{Actual depth of the object}}=\frac{\mu_{air}}{\mu_{water}}$

$\frac{d}{30}=\frac{1}{\sqrt{2}}$

d = $\frac{30}{\sqrt{2}}$ cm

d = $15\sqrt{2}$ ≈ 21.21 cm

Therefore, apparent depth of the pool will be 21.21 cm.