determine by substitution,if 2 is the root of 2x-3=1
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Step-by-step explanation:
Given to check whether 3 is a root of the equation
x
2
−4x+3
+
x
2
−9
=
4x
2
−14x+16
Here,
LHS=
x
2
−4x+3
+
x
2
−9
and RHS=
4x
2
−14x+16
Substitute x=3 in LHS
⇒
3
2
−4(3)+3
+
3
2
−9
⇒
9−12+3
+
9−9
⇒
0
+
0
=0
∴LHS=0
Similarly substitute x=3 in RHS
⇒
4(3)
2
−14(3)+16
⇒
4×9−42+16
⇒
36−42+16
⇒
52−42
=
10
∴RHS=
10
Now, we can observe that
LHS
=RHS
∴x=3 is not a solution or root for the equation
x
2
−4x+3
+
x
2
−9
=
4x
2
−14x+16
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