Math, asked by divyanshi9240, 7 months ago

Determine by substitution if:
3 is the root of
 \frac{x + 1}{2}  +  \frac{x - 1}{2}  = 3
can you give me fourmula​

Answers

Answered by chhotiroy343
8

Answer:

 \frac{x + 1}{2}  +  \frac{x - 1}{2}  = 3

 \frac{x + 1 + x - 1}{2}  = 3

 \frac{2x}{2}  = 3

x = 3

Answered by Anonymous
111

\color{red}{\large\underline{\underline\mathtt{Question:}}}

\mathtt{\mapsto \dfrac{x + 1}{2} + \dfrac{x - 1}{2} = 3}

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\color{purple}{\large\underline{\underline\mathtt{To\:Find:}}}

\textit{To find whether 3 is the root the the equation}

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\color{blue}{\large\underline{\underline\mathtt{Concept:}}}

\textit{By solving the equation , or Putting the value}\textit{of 3 on the equation we can determine that}\textit{whether 3 is the root of the equation or not}

______________________________________

\color{magenta}{\large\underline{\underline\mathtt{Solution:}}}

\mathtt{\mapsto \dfrac{x + 1}{2} + \dfrac{x - 1}{2} = 3}

\Rightarrow \dfrac{x + 1 + (x - 1)}{2} = 3

\Rightarrow \dfrac{x + 1 + x - 1}{2} = 3

\Rightarrow \dfrac{x + \cancel{1} + x -  \cancel{ 1}}{2} = 3

\Rightarrow \dfrac{x  + x}{2} = 3

\Rightarrow \dfrac{2x}{2} = 3

\Rightarrow 2x = 3 \times 2

\Rightarrow 2x = 6

\Rightarrow x = \dfrac{6}{3}

\Rightarrow x = \dfrac{\cancel{6}}{\cancel{3}}

\Rightarrow x = 3

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\mathtt{\therefore 3\:is\:the\:root\:of\:the\:equation}

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