determine by substitution, if: 5 is the root of x-3=6
Answers
Answered by
6
Solution :-
We have to determine by substitution, if 5 is the root of x - 3 = 6
If, x = 5
Putting the value of x = 5 in the above, we get.
R.H.S. = 5 - 3 = 2
L.H.S. = 6
L.H.S. ≠ R.H.S.
So, 5 is not the solution of x - 3 = 6
Answer.
We have to determine by substitution, if 5 is the root of x - 3 = 6
If, x = 5
Putting the value of x = 5 in the above, we get.
R.H.S. = 5 - 3 = 2
L.H.S. = 6
L.H.S. ≠ R.H.S.
So, 5 is not the solution of x - 3 = 6
Answer.
Answered by
2
Given equation is,
x - 3 = 6 ............... (1)
Here, we have to find out that whether 5 is the root of given equation or not.
For this, we have to show that,
L.H.S = R.H.S
From the equation,
R.H.S = 6
Now, if L.H.S is also 6 then 5 will be the root of the given equation.
Put x = 5 in the L.H.S of equation (1)
L.H.S = x - 3
L.H.S = 5 - 3
L.H.S = 2
which clearly shows that,
L.H.S ≠ R.H.S
Hence, "5" is not a root of the given equation x - 3 = 6
Hope it will help you. Thanks
x - 3 = 6 ............... (1)
Here, we have to find out that whether 5 is the root of given equation or not.
For this, we have to show that,
L.H.S = R.H.S
From the equation,
R.H.S = 6
Now, if L.H.S is also 6 then 5 will be the root of the given equation.
Put x = 5 in the L.H.S of equation (1)
L.H.S = x - 3
L.H.S = 5 - 3
L.H.S = 2
which clearly shows that,
L.H.S ≠ R.H.S
Hence, "5" is not a root of the given equation x - 3 = 6
Hope it will help you. Thanks
Similar questions