Determine change in momentum for quarter movement of a circular
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hey here is your answer
On the first line we state that the change in momentum is equal to the mass times the change in velocity. In line two we change delta v to the quantity of the final velocity minus the original velocity, as one can do with any delta quantity. The mass is distributed over the two velocities on line three.
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On the first line we state that the change in momentum is equal to the mass times the change in velocity. In line two we change delta v to the quantity of the final velocity minus the original velocity, as one can do with any delta quantity. The mass is distributed over the two velocities on line three.
hope this helps you dear ☺️☺️☺️☺️☺️☺️☺️☺️
bê brainly ✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️
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