Question

determine de broglie wavelength of an electron of electron has been accelerated by applying potential difference of 150 volt ​

Answer 1

Answer:

Explanation:

The k.e of an electron accelerated through a potential difference of V volts is given by the equation:

½ mv2 = eV

electron charge (1.6x10-19 C)

(You must be given the electron charge and Planck's constant in order to answer this question)

and so v = √(2eV/m) = 7.26x106 m/s  

∴ wavelength = h/mv

= h/[9.11x10- 31x7.26x106]

= 1x10-10 = 0.1 nm

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