Question

Determine determine the AP whose fourth term is 6 and 7th term is 9

Answer 1

Answer:

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Answer 2

The required AP= 3 , 4, 5 ,6...

Explanation:

Let a be the first term and d be the common difference in AP a , a+d , a+2d , a+3d ,....

nth Term of AP. =$a_n=a+(n-1)d$

Given :  Fourth term is 6.

i.e. $a+3d = 6$  (1)

7th term is 9

i.e.  $a+6d=9$    (2)

Eliminate (1) from (2) , we get

$3d= 3\Rightarrow\ d=1$

Put d- 1 in (1) , we get

$a+3(1)=6\\\\\Rightarrow a=3$

The required AP is 3 , 3+1 , 3+2(1) , 3+3(1).....

Hence, the required AP= 3 , 4, 5 ,6...

# Learn more :

Determine the AP whose 3rd term is 5 and the 7th term is 9.

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