Question

determine discharge in the best triangular channel with 1 m flow depth and 2 m/s velocity

Answer 1

The answer is "1 m3/s"

Explanation:

Since, we know that flow in a channel can either be given by dividing the volume by the time or by multiplying the area with the velocity. Hence, we can do it as.

Flow = area x velocity  ................................. eq (1)

Flow = volume/ time    .................................. eq (2)

Thus, we need to make assumption about the base of the channel

Since, we know that

Area of triangle = 1/2 (base*height)

As we are given with the depth, if we assume the base as 1m, then

Area of triangle = 1/2 (1)(1) = 0.5 m2

Then,

Flow = 0.5 * 2 = 1 m3/s