Question

Determine force on 2c charge in arrangement of charges kept at corners of a square of side 2m then k is coulomb's constant

Answer 1

The force on the charge is F = 4.5 x 10^19 N.

Explanation:

The coulomb force between two charged bodies is:

F = K (q1 . q2) / d^2

As q1 = q2 = 2 C

F = 9 x 10^9 x 2 / (2)^2

F = 18 x 10^19 / 4

F = 4.5 x 10^19 N

Thus the force on the charge is F = 4.5 x 10^19 N.

Also learn more

The electrostatic force between charges of 200 micro-coulomb and 500 micro-coulomb placed in free space is 5 gf find the distance between the two charges take g is equal to 10 metre per second square​ ?

https://brainly.in/question/9871565

Answer 2

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Given :

• Charge 1 (Q1) = 2 C
• Charge 2 (Q2) = 2 C
• Distance (d) = 2 m

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To Find :

• Value of Force

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Solution :

Use Coloumb's Law :

$\large{\boxed{\boxed{\rm{F \: = \: k \dfrac{Q_1 Q_2}{d^2}}}}} \\ \\ \implies {\sf{F \: = \: k \dfrac{2 \: \times \: 2}{2^2}}} \\ \\ \implies {\sf{F \: = \: k \dfrac{2^2}{2^2}}} \\ \\ \implies {\sf{F \: = \: k}} \\ \\ \implies {\sf{F \: = \: 9 \: \times \: 10^9}} \\ \\ {\underline{\sf{\therefore \: Force \: is \: 9 \: \times \: 10^9 \: N}}}$