Determine graphically the coordinates of the vertices of a triangle, the equations of whose sides are:
(i) y = x, y = 2x and y + x = 6
(ii) y = x, 3y = x, x + y = 8
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Triangle
Step-by-step explanation:
(i) y = x, y = 2x and y + x = 6
To draw y = x, we will plot the points (1,1) and (0,0).
To draw y = 2x, we will plot the points (1,2) and (0,0).
To draw x + y = 6, we will plot the points (0,6) and (6,0).
The shaded region is the triangle formed by the 3 lines.
= Area of ∆ABC - Area of ∆ADC
= 1/2 height of ∆ABC * AC + 1/2 height of ∆ADC * AC
= 1/2 * 4 * 6 + 1/2 * 3 * 6
= 21 sq. cm.
Vertices of ∆ABD are A(0,0) , B(2,4), D(3,3). Please refer the attached picture for the graph.
(ii) y = x, 3y = x, x + y = 8 --- Please solve using similar steps.
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