Question

determine graphically wheather the following system of equations:3x-4y=1;8y-6x=4 is consistent or inconsistent​

Answer 1

Answer:

inconsistent

Step-by-step explanation:

the given equations

3x-4y=1

8y-6x=4

a1/a2not equal to b1/b2 is not equal to c1/c2

Answer 2

Answer:

The linear equation is inconsistent

Step-by-step explanation:

The given equation is 3x–4y = 1 and 8y – 6x =3 Now, let us find at least two solutions to each of the above equations, as shown in the following tables.

Equation 1

$4y=-3x-1\\ y=\frac{3x+1}{4} \\x=0 \\y=\frac{0+1}{4}\\y=\frac{1}{4}\\x=1\\y=\frac{3+1}{4}\\y=\frac{4}{4}\\y=1\\x=2\\y=\frac{3*2+1}{4}\\y=\frac{7}{4}\\x=-1\\y=\frac{-3+1}{4}\\y=\frac{-2}{4}\\y=\frac{-1}{2}\\x=-2\\y=\frac{-6+1}{4}\\y=\frac{-5}{4}\\x=-3\\y=\frac{-9+1}{4}\\y=\frac{-8}{4}\\\\y=-2$

$x=0,y=\frac{1}{4}$    

$x=1,y=1\\x=2,y=\frac{7}{4}$  

$\\ x=-1,y=\frac{-1}{2}\\\\\\ x=-2,y=\frac{-5}{4}\\\\\\ x=-3,y=-4$

Equation 2:

$8y=6x+4\\ y=\frac{6x+4}{8} \\x=0 \\y=\frac{0+4}{4}\\ y=1\\x=1\\y=\frac{6+4}{8}\\y=\frac{5}{4}\\x=2\\y=\frac{12+4}{8}\\y=2\\x=-1\\y=\frac{-6+4}{8}\\y=\frac{-2}{8}\\y=\frac{-1}{4}\\x=-2\\y=\frac{-12+4}{8}\\y=\frac{-8}{8}\\y=-1\\x=-3\\y=\frac{-18+4}{8}\\y=\frac{-14}{8}\\\\y=\frac{-7}{4}$

$x=0,y=1\\x=1,y=\frac{5}{4}\\x=2,y=2\\x=-1,y=\frac{-1}{4}\\x=-2,y=-2\\x=-3,y=\frac{-7}{4}$