Determine how far an object must be placed in front of a converging lens of focal length 15 cm in order to produce an erect (upright) image of linear magnification 4.
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Answer:
The distance where the object must be placed in front of a converging lens is 11.25 cm
Explanation:
According to the problem the focal length, l= 15cm
and magnification,m is 4
Let the distance the object must be placed: d
As we know the magnification formula:
m= u/d
4= u/d
u= 4d
Now according to the lens formula:
1/u - 1/d= 1/l
=> 1/4d - 1/d= 1/15
=> d= -11.25
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