determine how many two digit numbers are divisible by 5
Answers
Step-by-step explanation:
The two-digit numbers which leave the remainder 1 when divided by 5
11,16,21,26,.......86,91,96
In this A.P :
a=11
d=16−11=5
l = 96
An =a+(n−1)d
96=11+(n−1)5
n−1= 85/5
n=17+1
n=18
Hence 18 two digit numbers are divisible by 5 such that reminder is 1.
Hope this is helpful
Answer:
18
Step-by-step explanation:
Smallest two digit number = 10
Smallest two digit number divisible by 5 = 10
Largest two digit number = 99
Largest two digit number divisible by 5 = 95
So, the range is 10 to 95.
We will use Arithmetic progression to find the answer.
AP = 10,15,20,25........95
a = 10
d = 15 - 10
= 5
l = 95
l = a + (n - 1)×d
95 = 10 + (n - 1)×5
95 - 10 = 5n - 5
85 = 5n - 5
5n = 85 + 5
5n = 90
n = 18
So, there are 18 two digit numbers that are divisible by 5.