Question

Determine in AP whose third Term is 16 and the 17th term exceeds the 5th term by 12

Answer 1

Answer: First term(a) = 14 and Common Difference (d) = 1

Series: 14,15,16,17,18,..........

Step-by-step explanation:

Third term = a+2d = 16      .......(i)

Seventeenth term = fifth term +12

      a+16d = a+4d + 12       ......(ii)

On solving (ii), we get, d = 1

Use this value in (I), we get, a=14

Therefore, series is 14,15,16,17,18....

Hope it Helped all.... :-)