Determine in AP whose third Term is 16 and the 17th term exceeds the 5th term by 12
Answers
Answered by
2
Answer: First term(a) = 14 and Common Difference (d) = 1
Series: 14,15,16,17,18,..........
Step-by-step explanation:
Third term = a+2d = 16 .......(i)
Seventeenth term = fifth term +12
a+16d = a+4d + 12 ......(ii)
On solving (ii), we get, d = 1
Use this value in (I), we get, a=14
Therefore, series is 14,15,16,17,18....
Hope it Helped all.... :-)
Similar questions