Determine k show that 3k-2,4k-6 and k+2 are 3 consecutive terms of AP
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a-d=3k-2
a=4k-6
a+d=k+2
3a=8k-6
12k-18=8k-6
4k=12
k=3
a=4k-6
a+d=k+2
3a=8k-6
12k-18=8k-6
4k=12
k=3
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