Determine k so that 3k-2, 2k^2-5k+8,4k+3 are the three consecutive terms of ap
Answers
Answered by
1
Answer:
Either k = 5/4 or k = 3.
Step-by-step explanation:
These are consecutive terms of an arithmetic progression if there is a common difference; i.e. if 2nd term - 1st term = 3rd term - 2nd term.
(2k²-5k+8) - (3k-2) = (4k+3) - (2k²-5k+8)
=> 2 ( 2k² - 5k + 8 ) = 4k + 3 + 3k - 2
=> 4k² - 10k + 16 = 7k + 1
=> 4k² - 17k + 15 = 0
=> ( 4k - 5 ) ( k - 3 ) = 0
=> k = 5/4 or k = 3
Answered by
0
Answer:
Step-by-step explanation:
2k^2-5k+8-3k-2=4k+32k^2-5k+8
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