Question

Determine k so that (3k-2) (4k-6) and (k+2) are three consecutive terms of an ap

Answer 1

Answer:

Value of k is 3.

Step-by-step explanation:

if a,b,c are in AP then 2b=a+c So in this case 2(4k-6)= (3k-2)+(k+2) => 4k =8k-12 =>4k=12 =>k =3.